本作业要求来自于：
1.字符串操作：
解析身份证号：生日、性别、出生地等。| 1 2 3 4 5 6 7 8 9 10 11 12 13 | code = input ( "请输入您的身份证号：" ); year = code[ 6 : 10 ]; month = code[ 10 : 12 ]; day = code[ 12 : 14 ]; province = code[ 0 : 2 ]; area = { '11' : '北京市' , '12' : '天津市' , '13' : '河北省' , '14' : '山西省' , '15' : '内蒙古自治区' , '21' : '辽宁省' , '22' : '吉林省' , '23' : '黑龙江省' , '31' : '上海市' , '32' : '江苏省' , '33' : '浙江省' , '34' : '安徽省' , '35' : '福建省' , '36' : '江西省' , '37' : '山东省' , '41' : '河南省' , '42' : '湖北省' , '43' : '湖南省' , '44' : '广东省' , '45' : '广西壮族自治区' , '46' : '海南省' , '50' : '重庆市' , '51' : '四川省' , '52' : '贵州省' , '53' : '云南省' , '54' : '西藏自治区' , '61' : '陕西省' , '62' : '甘肃省' , '63' : '青海省' , '64' : '宁夏回族自治区' , '65' : '新疆维吾尔自治区' , '71' : '台湾省' , '81' : '香港特别行政区' , '82' : '澳门特别行政区' } print ( "你所查询的身份证归属地为：" + area.get(province)); print ( "出生日期是{}年{}月{}日" . format (year,month,day)); sex = code[ - 2 ]; if int (sex) % 2 = = 0 : print ( "性别为女" ); else : print ( "性别为男" ) |
网址观察与批量生成
| 1 2 | for i in range ( 2 , 16 ): print ( 'http://news.gzcc.cn/html/xiaoyuanxinwen/' + str (i) + '.html' ) |
凯撒密码编码与解码
| 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 | def encryption(): str_raw = input ( "请输入明文：" ) k = int ( input ( "请输入位移值：" )) str_change = str_raw.lower() str_list = list (str_change) str_list_encry = str_list i = 0 while i < len (str_list): if ord (str_list[i]) < 123 - k: str_list_encry[i] = chr ( ord (str_list[i]) + k) else : str_list_encry[i] = chr ( ord (str_list[i]) + k - 26 ) i = i + 1 print ( "加密结果为：" + "".join(str_list_encry)) def decryption(): str_raw = input ( "请输入密文：" ) k = int ( input ( "请输入位移值：" )) str_change = str_raw.lower() str_list = list (str_change) str_list_decry = str_list i = 0 while i < len (str_list): if ord (str_list[i]) > = 97 + k: str_list_decry[i] = chr ( ord (str_list[i]) - k) else : str_list_decry[i] = chr ( ord (str_list[i]) + 26 - k) i = i + 1 print ( "解密结果为：" + "".join(str_list_decry)) while True : print (u "1. 加密" ) print (u "2. 解密" ) choice = input ( "请选择：" ) if choice = = "1" : encryption() elif choice = = "2" : decryption() else : print (u "您的输入有误！" ) |
2.英文词频统计预处理
| 1 2 3 4 5 6 7 8 9 10 11 12 | url = ''' WHEN MINUTES BECOME HOURS WHEN DAYS BECOME YEARS AND I DON’T KNOW WHERE YOU ARE COLOR SEEMS SO DULL WITHOUT YOU ''' str1 = url.lower() str2 = str1.replace( "," ,"") str3 = str2.replace( "'" ,"") print (str3) print (str3.split()); print (str3.count( 'we' )) |
- 凯撒密码：从文件读入密函，进行加密或解密，保存到文件。
- 词频统计：下载一首英文的歌词或文章或小说，保存为utf8文件。从文件读入文本进行处理。
凯撒密码
词频统计
text=open('gril.txt','r',encoding='utf-8') text=text.read() x=",？！." for xx in x: text1=text.replace(xx,' ') print(text1) text2=open('gril1.txt','a',encoding='utf-8') text2.write(text1)
4.函数定义
- 加密函数
def encryption(): str_raw = input("请输入明文：") k = int(input("请输入位移值：")) str_change = str_raw.lower() str_list = list(str_change) str_list_encry = str_list i = 0 while i < len(str_list): if ord(str_list[i]) < 123-k: str_list_encry[i] = chr(ord(str_list[i]) + k) else: str_list_encry[i] = chr(ord(str_list[i]) + k - 26) i = i+1 print ("加密结果为："+"".join(str_list_encry))
- 解密函数
def decryption(): str_raw = input("请输入密文：") k = int(input("请输入位移值：")) str_change = str_raw.lower() str_list = list(str_change) str_list_decry = str_list i = 0 while i < len(str_list): if ord(str_list[i]) >= 97+k: str_list_decry[i] = chr(ord(str_list[i]) - k) else: str_list_decry[i] = chr(ord(str_list[i]) + 26 - k) i = i+1 print ("解密结果为："+"".join(str_list_decry))
- 读文本函数
def readFile(filePath): file=open(filePath,'r',encoding='utf-8') return file.read()